a sphere of mass 40 kg is placed at a distance of 0 .9 m from a sphere of 60 kg if the two sphere attract each other with the force of 0.196×10^-6. find the value of gravitational constant . given 1kgf =9.8
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Answer:
Distance (G)=20cm=0.2m
Mass (M1)=40kg Mass (m2)=15kg
Force (F)=0.1 milligram wt
=0.1×10−3×980 dyne
=98×10−3 dyne
=98×10−8N
=9.8×10−9N
F=R2GM1M2
G=M1M2Fk2=40×159.8×10−7×0.2×0.2
=4×1598×2×2×10×10×10×1010−7
=6.5×10−11m2/kss
Explanation:
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