Question

A sphere of mass 40 kg is placed at a distance of 0.9m from a spere of 60 kg.
If the two spheres attract each other with a force of 1.96×10^-8 N. Find the value of gravitational constant.

Answer 1

F = Gm1m2/r²

G = Fr²/m1m2

G

$= \frac{1.96 \times {10}^{ - 8} \times {(0.9)}^{2} }{40 \times 60} \\ = \frac{1.96 \times 0.81 \times {10}^{ - 8} }{2400} \\ = 0.0006615 \times {10}^{ - 8} = 6.615 \times {10}^{ - 11}$

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