A sphere of mass 40 kilogram is attracted by a second sphere when their centres are 20 CM apart with a force of 0. 1 mg w e i g h t calculate the value of gravitational constant
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Hi friend,
F= mg =0.1×10
F=1N
By gravitational law,
F=GMm/r²
G= F r² /Mm
G=1×(0.2)²/ 40×0.1
G=0.04/4
G=0.01 N m² kg ^-².
Hope this helped you a little!!!
F= mg =0.1×10
F=1N
By gravitational law,
F=GMm/r²
G= F r² /Mm
G=1×(0.2)²/ 40×0.1
G=0.04/4
G=0.01 N m² kg ^-².
Hope this helped you a little!!!
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