A sphere of mass 5kg having a velocity 4m/s and another sphere of mass 4kg having a velocity of 2m/s in the opposite direction. After the collision they stick each other and move with common velocity, their total initial momentum of the system is
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M1u1+M2u2
5×4+4×[-2]
12kgm/s
shreya0803:
thank you
Answered by
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Here,
Initial momentum = m1*v1+m2*v2
=5*4-4*2
[(-ve) sign is due to opposite in direction]
=12kgm/s
After the collision,
Initial momentum = final momentum
m1*v1 - m2*v2 = (m1+m2) *v
5*4-4*2 = (5+4)*v
12 = 9*v
=> v = 1.33m/s
That's your solution hope this solution will help you to understand
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