Question

A sphere of mass m and radius r rolls on a
horizontal plane without slipping with a
speed u. Now it rolls up vertically, then
maximum height it would be attain will be
5u² 7u²
u²
4)
34²
1) 48
2)
3)
2g
10g
2g​

Answer 1

Answer:

at no slipping condition for sphere,

                           u=ωr

                    ⇒ω=  

r

u

​  

 

From energy conservation principle,

       Initial energy= Final energy

⇒Linear kinetic energy+rotational energy=final potential energy

⇒  

2

1

​  

mv  

2

+  

2

1

​  

Iω  

2

=mgh

⇒  

2

1

​  

mu  

2

+  

2

1

​  

×  

5

2

​  

mr  

2

(  

r

u

​  

)  

2

=mgh

⇒  

2

1

​  

mu  

2

+  

5

1

​  

mu  

2

=mgh

⇒  

10

7

​  

mu  

2

=mgh

⇒h=  

10g

7u  

2

 

​

Step-by-step explanation: