a sphere of maximum value is cut out from a solid hemisphere of radius r. What is the ratio of the volume of the hemisphere to that of the cutout sphere?
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A sphere ⚾ with maximum volume can be cut from a solid hemisphere will be one whose
Diameter is equal to the the Radius of the hemisphere
let r be the radius of hemisphere
Then radius of sphere = r / 2
volume of hemisphere. = 2 / 3π r^3
volume of sphere = 4 / 3π (r/2) ^ 3
RATIO = VOL.OF HEMI,SPH / VOL,OF, SPH
= 2/3πr^3. / 4/3π((r/2))^3
= 4
Therefore. ratio = 4 : 1
Diameter is equal to the the Radius of the hemisphere
let r be the radius of hemisphere
Then radius of sphere = r / 2
volume of hemisphere. = 2 / 3π r^3
volume of sphere = 4 / 3π (r/2) ^ 3
RATIO = VOL.OF HEMI,SPH / VOL,OF, SPH
= 2/3πr^3. / 4/3π((r/2))^3
= 4
Therefore. ratio = 4 : 1
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Answered by
4
Answer:
A sphere ⚾ with maximum volume can be cut from a solid hemisphere will be one whose
Diameter is equal to the the Radius of the hemisphere
let r be the radius of hemisphere
Then radius of sphere = r / 2
volume of hemisphere. = 2 / 3π r^3
volume of sphere = 4 / 3π (r/2) ^ 3
RATIO = VOL.OF HEMI,SPH / VOL,OF, SPH
= 2/3πr^3. / 4/3π((r/2))^3
= 4
Therefore. ratio = 4 : 1
Attachments:
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