Physics, asked by resh1, 1 year ago

A sphere of radius 0.03 m has a point charge q = 7.6 µC located at its centre. Find the electric flux through it.

Answers

Answered by Pranav3103
30
electric flux is independent of radius but dependent on charge enclosed and equal to 1/ε times the charge enclosed
hence electric flux= 7.6×10⁻⁶/8.85×10⁻¹²

Answered by archanajhaasl
3

Answer:

The electric flux through the center of the sphere is 8.58×10⁵Nm²C⁻¹.

Explanation:

The electric flux through the center of the sphere is given as,

\phi=\frac{q}{\epsilon_o}             (1)

Where,

Ф=flux through the center of the sphere

q=charge placed at the center of the sphere

∈₀=permittivity of free space=8.8542×10⁻¹²C²N⁻¹m⁻²

From the question we have,

Charge placed at the center of the sphere(q)=7.6μC=7.6×10⁻⁶C

By placing the value of the charge and permittivity in equation (1) we get;

\phi=\frac{7.6\times 10^-^6}{8.8542\times 10^-^1^2}

\phi=8.58\times 10^5Nm^2C^-^1

Hence, the electric flux through the center of the sphere is 8.58×10⁵Nm²C⁻¹.

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