a sphere of radius 1 cm has potential of 8000 volt the energy density near the surface of square will be
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density near its surface will be ......
(A) 64 × 105 (J/m3) (B) 2.83 (J/m3)
(C) 8 × 103 (J/m3) (D) 32 (J/m3)
Solution: Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
(A) 64 × 105 (J/m3) (B) 2.83 (J/m3)
(C) 8 × 103 (J/m3) (D) 32 (J/m3)
Solution: Answer: (B) 2.83 (J/m3)
Energy density = (1/2)∈0E2
= (1/2) × 8.86 × 10–12 × (v/r)2
= 4.43 × 10–12 × [(8000) / (10–2)]2
= 283.5 × 10–2
= 2.83 J/m3
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