Question

A sphere of radius 10 cm carries a charge of 1 micro coulomb. calculate the electric fielt intensity
a) at a Istance 30cm from the centre of the sphere
b) at the surface of the Sphere
c) of a distance of 5 cm from the centre of the sphere
​

Answer 1

a sphere of radius 10 cm carries a change of 1 microcolomb calculator the electric field interested

Explanation:

at the a lstance 30 cm of the from the centre of the sphere in is the called of the sphere

at the surface of the are is the into of the sphere of the sphere of the liquid and is called sphere

the of a distance between the two times of are 5 cm from the centre of the sphere

Answer 2

Answer:

A sphere of radius 10 cm with a charge of 1 micro coulomb,

1. the electric field at a distance of 30 cm outside is $10^{5} N/C$
2. the electric field on the surface is $9*10^{5} N/C$
3. the electric field inside the sphere  $r=5cm$ is $36*10^{5} N/C$

Explanation:

• The electric field is the electrostatic force experienced by a unit charge due to another charge

• The electric field due to a sphere with surface charge $q$ and radius $R$ at a distance $r$ from the center of the sphere (outside), is given by the Gauss law as

                        $E_{out} =\frac{q}{4\pi \varepsilon _0r^{2} }$

• For electric field on the surface the distance  $r=R$

                     $E_{on} =\frac{q}{4\pi \varepsilon _0R^{2} }$

• The electric field inside the sphere at a distance of x inside is  

                    $E_{in} =\frac{q}{4\pi \varepsilon _0x^{2} }$

  where the value of  $\frac{1}{4\pi \varepsilon _0} =9*10^{9}$

From the question, we have

The surface charge of the sphere $q=1*10^{-6}C$

the distance where the field is to be calculated $r=30cm=0.30m$

the outside electric field is

$E_{out} =\frac{9*10^{9}*10^{-6} }{(0.30)^{2} } =10^{5} N/C$

the radius of the sphere $R=10cm=0.10m$

electric field on the surface is $E_{on} =\frac{9*10^{9}*10^{-6} }{(0.10)^{2} } =9*10^{5} N/C$

inside distance $x=5cm=0.05m$

the electric field inside the sphere is  $E_{in} =\frac{9*10^{9}*10^{-6} }{(0.05)^{2} } =36*10^{5} N/C$