A sphere of radius 10 cm is supplied a charge of 40 is. Find the work done to give it a charge of 10 esu more.
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work done=change in potential energy
=Uf-Ui
=2k/5R(Q2-Q1)
=2k/5R*30 *3.33*10^-10
=2*9*30*3.33*10/5*10
=360J
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