Physics, asked by kaushikdey, 1 year ago

A sphere of radius 10 cm is supplied a charge of 40 is. Find the work done to give it a charge of 10 esu more.​

Answers

Answered by PSN03
0

work done=change in potential energy

=Uf-Ui

=2k/5R(Q2-Q1)

=2k/5R*30 *3.33*10^-10

=2*9*30*3.33*10/5*10

=360J

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