Physics, asked by aaemranaae, 5 months ago

A sphere of radius 12cm contains charge density 6/3

.

What are the electric field at (i) R= 8cm and (ii) r= 15cm.​

Answers

Answered by Mariyam121
0

Explanation:

.(a) Radius of the spherical conductor, r = 12 cm = 0.12 m

Charge is uniformly distributed over the conductor, q = 1.6 × 10 -7 C

Electric field inside a spherical conductor is zero. This is because if there is field inside the conductor, then charges will move to neutralize it.

(b) Electric field E just outside the conductor is given by the relation,

Where,

= Permittivity of free space

Therefore, the electric field just outside the sphere is 105 N C-1

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