Question

A sphere of radius 1cm has potential of 8000v, then energy density near its surface will be

Answer 1

Answer:

Energy density= (1/2)∈0E2

= (1/2) × 8.86 × 10–12 × (v/r)2

= 4.43 × 10–12 × [(8000) / (10–2)]2

= 283.5 × 10–2

= 2.83 J/m3

hope it helps :)