Question

A sphere of radius 20 cm having potential 8X103 V on it, then Charge on it is ______, k = 9 x 109 MKS​

Answer 1

Answer:

Electric Potential ( V ) = k × Q / R

R = radius of sphere .

Explanation:

★ V = 9 × 10⁹ × Q / 20 × 10-³ m

» 8 × 10³ = 9 × 10⁹ × Q / 20 × 10-³ m

» 8 × 10³ × 20 × 10-³ = 9 × 10⁹ × Q

» 160 = 9 × 10⁹ × Q

» Q = 160 × 10-⁹ / 9

★ Q ≈ 18 × 10-⁹ C ≈ 18 n C ( nano coulumb ) ★