a sphere of radius 4.2 cm is melted and recast in a shape of cylinder of radius 6cm . find hight of the cylinder
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s(r)=4.2
C(r)=6
C(r)=?
4/3πr3=πr2h
h=4/3×42×42×42/10×10×10×6×6
h= 343/125
h=2.74cm
I hope it help you
C(r)=6
C(r)=?
4/3πr3=πr2h
h=4/3×42×42×42/10×10×10×6×6
h= 343/125
h=2.74cm
I hope it help you
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