Question

A sphere of radius 5cm has a charge of 31.41 micro C calculate the surface density of charge?

Answer 1

Explanation:

The surface density of charge of the sphere is 999.8 C/ m².

The radius of sphere ( r ) = 5 cm

= 5x10⁻² m

Thus, Area ( a ) = 314.16x10⁻⁴ m²

Charge of sphere ( q ) = 31.41 micro Coulomb

= 31.41 x 10⁻⁶ C

Therefore, The surface density of charge = q / a

= 31.41 x 10⁻⁶ C/ 314.16x10⁻⁴ m²

= 999.8 C/ m²

Answer 2

Answer:

10^-3 C/m²

Explanation:

charge density=charge on the surface/ area of surface

charge density={(31.41×10^-6)/4π(5×10^-2)²} C/m²

={(31.41×10^-6)/(4×3.141×25×10^-4)} C/m²

=10^-3 C/m²