A sphere of radius is 6cm is dropped in a right circular cylinder
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Step-by-step explanation:
Hi ,
1 ) diameter of the sphere ( d ) = 6cm
radius of the sphere ( r ) = d/2 = 6/2 = 3cm
2 ) diameter of the cylindrical vessel ( D ) = 12 cm
radius of the cylindrical vessel ( R ) = 12/2 = 6 cm
level of water raised = h cm
according to the problem given ,
volume of the water raised in the vessel = volume of the sphere
πR²h = 4/3 × πr³
h = ( 4 × r³ ) / ( 3 × R² )
h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )
h = 1 cm
Therefore ,
level of water raised in the vessel = h = 1 cm
I hope this helps you.
: )
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