Question

A sphere of radius R is connected by wire with a smaller sphere of radius r.if the spheres were charged with Q and q . Respectively . Show that
The electric field is higher at the surface of the smaller sphere??

Answer 1

Explanation:

Electric field on the surface of conducting sphere=

R

2

kQ

according to given condition

r

1

2

kq

1

=

r

2

2

kq

2

⟹

q

2

q

1

=

r

2

2

r

1

2

−(1)

ratio of potentials at centre

=

r

2

kq

2

r

1

kq

1

=

q

2

q

1

⋅

r

1

r

2

substituting

q

2

q

1

from (1)

we get

ratio=

r

2

r

1

Ans.