A sphere uniformly charged with a charge density d has a radius R. A spherical cavity of radius R/4 is made in it such that centre of original sphere lies on the circumference what is the electric field at point P? P lies on the circumference of original sphere.
Answers
Answered by
5
electric field is equal to...
1/4piE x 63/64 xd(4piR^2)/R^2
.....
Similar questions