A spherical airbubble is formed in water at a depth of 1metre from its surface .s surfacetention of water is 75.calculate the pressure inside the bubble ,if pressure of air over the surface of water is 0.78meter of mercury
kvnmurty:
radius of bubble is missing.
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Pressure inside bubble in air - Pressure outside the bubble in water =
= 2 * Surface tension / Radius of bubble
P₂ - P₁ = 2 S / R
P₁ = Pressure outside the water surface + Pressure due to water column of 1meter
= 0.78 meter * Density of mercury * g + 1 meter * density of water * g
= 0.78 m * 13,546 kg/m³ * 9.81 m/s² + 1 m * 1000 kg/m³ * 9.81 m/s²
= 103,651.283 + 9810 = 113461.283 Pa
P₂ = P₁ + 2 S / R = 113,461.283 + 2 * 0.075 / R = 113,461.283 Pascal + 0.15/R
where R is the radius of bubble in meters
= 2 * Surface tension / Radius of bubble
P₂ - P₁ = 2 S / R
P₁ = Pressure outside the water surface + Pressure due to water column of 1meter
= 0.78 meter * Density of mercury * g + 1 meter * density of water * g
= 0.78 m * 13,546 kg/m³ * 9.81 m/s² + 1 m * 1000 kg/m³ * 9.81 m/s²
= 103,651.283 + 9810 = 113461.283 Pa
P₂ = P₁ + 2 S / R = 113,461.283 + 2 * 0.075 / R = 113,461.283 Pascal + 0.15/R
where R is the radius of bubble in meters
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