Physics, asked by anu7640, 1 year ago

   A spherical airbubble is formed in water at a depth of 1metre from its surface .s  surfacetention of water is 75.calculate the pressure inside the bubble ,if pressure of air over the surface of water is 0.78meter of mercury 











kvnmurty: radius of bubble is missing.
kvnmurty: surface tension is 75 cgs units, 0.075 N/meter

Answers

Answered by kvnmurty
0
Pressure inside bubble in air - Pressure outside the bubble in water = 
                  = 2 * Surface tension / Radius of bubble

P₂ - P₁ = 2 S / R

P₁ = Pressure outside the water surface + Pressure due to water column of 1meter
      = 0.78 meter * Density of mercury * g + 1 meter * density of water * g
      = 0.78 m * 13,546 kg/m³ * 9.81 m/s² + 1 m * 1000 kg/m³ * 9.81 m/s²
      = 103,651.283 + 9810 = 113461.283  Pa

P₂ = P₁ + 2 S / R = 113,461.283 + 2 * 0.075 / R = 113,461.283 Pascal + 0.15/R 

               where R is the radius of bubble in meters

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