Question

-
A spherical ball contracts in radius by 2%, when
subjected to a normal uniform force. The volumetric
strain produced in ball is
(1) 6 x 10-2
(2) 2 x 10-2
(3) 4x 10-2
(4) 10-2

Answer 1

Answer:

The volumetric  strain produced in ball is 0.06

Explanation:

As we know that the volume of the sphere is given as

$V = \frac{4}{3} \pi r^3$

now we know that

$dV = 4\pi r^2 dr$

now in order to find the fractional change in the volume we will divide above two equations

So we will have

$\frac{dV}{V} = \frac{4\pi r^2dr}{\frac{4}{3}\pi r^3}$

now we have

$\frac{dV}{V} = 3\frac{dr}{r}$

as we know that

$\frac{dr}{r} = 0.02$

so we have

$\frac{dV}{V} = 3(0.02)$

$\frac{dV}{V} = 0.06$

#Learn

Topic : Volumetric Strain

https://brainly.in/question/7889383

Answer 2

Answer:

6*10^_2 Option 1 is correct

Explanation: