A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57cm2,find the radius of the original spherical ball.
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Curved surface area of a sphere=4×pi×r²
Csa of half of sphere(or)hemisphere=2×pi×r²
Given CSA of hemisphere=56.57cm²
Radius of hemisphere=radius of complete sphere
Acc to the question
2×pi×r²=56.57
r²=56.57/2×pi
=56.57/6.28
r²=9.007 =9(approx)
r=root of 9 = 3cm
Hence the radius of sphere is equal to 3cm
Csa of half of sphere(or)hemisphere=2×pi×r²
Given CSA of hemisphere=56.57cm²
Radius of hemisphere=radius of complete sphere
Acc to the question
2×pi×r²=56.57
r²=56.57/2×pi
=56.57/6.28
r²=9.007 =9(approx)
r=root of 9 = 3cm
Hence the radius of sphere is equal to 3cm
vishagh:
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This should help.
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