A spherical ball of diameter 21 cm is melted and recast into cubes each of side 1 cm. Find the number of cubes so formed
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Solution :-
Diameter of sphere = 21 cm
Radius = 21/2 = 10.5 cm
Volume of sphere = 4/3πr³
⇒ 4/3*22/7*10.5*10.5*10.5
⇒ 101871/21
= 4851 cu cm
Volume of cube = Edge*Edge*Edge
⇒ 1*1*1
= 1 cu cm
Let number of cubes formed be n
Volume of sphere = n(Volume of cube)
⇒ 4851 = n × 1
⇒ n = 4851
So, number of cubes formed is 4851
Answer.
Diameter of sphere = 21 cm
Radius = 21/2 = 10.5 cm
Volume of sphere = 4/3πr³
⇒ 4/3*22/7*10.5*10.5*10.5
⇒ 101871/21
= 4851 cu cm
Volume of cube = Edge*Edge*Edge
⇒ 1*1*1
= 1 cu cm
Let number of cubes formed be n
Volume of sphere = n(Volume of cube)
⇒ 4851 = n × 1
⇒ n = 4851
So, number of cubes formed is 4851
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