Question

a spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls if the diameter of two balla be 3/2cm find the diameter of third ball​

Answer 1

Answer:

you are missing on this question. this question Belongs to RD Sharna. in this question diameter of two balls are 3/2 and 2 OK. I give you answer.

Step-by-step explanation:

volume of big spherical ball= Va+Vb+Vc

• 4/3π(3/2)^2 = 4/3π(3/2/2)^3+4/3π(2/2)^3+4/3π(d/2)^3
• 4/3π(27/8) = 4/3π{27/64+1+d^3/8}
• 27/8 = 27/64+1+d^3/8

take lcm

• 27/8 = 27+64+8d^3/64
• 27 = 91+8d^3/8
• 27*8=91+8d^3
• 216 - 91 = 8d^3
• 125/8 = d^3
• (5/3)^3= d^3

so d=5/3

now your answer of the third spherical ball is 5/2