Question

a spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. the diameter of two of these are 1.5 and 2 cm resp. the diameter of the third ball is
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Answer 1

Answer:

In this case the volume of the initial spherical ball will be the sum of the volumes of the new three balls.

  Volume of a sphere =34πr3

As the diameter of the given sphere is 3cm then its radius =23=1.5cm ......... as [radius=2diameter

The radius of other two balls will be .75cm and 1cm.

Let the radius of the third new ball be Rcm.

Volume of the three new sphere = Volume of old sphere

⇒ 34π.753 + 34π.13 + 34π.R3 = 34π1.53

⇒ .753 + 13 + R3 =   1.53

⇒ 0.421875+1+R3=3.375

⇒ 1.421875+R3=3.375

⇒ R3=1.953125

⇒ R=1.95312531

HOPE IT HELPS YOU