Question

A spherical ball of lead if diameter 3cm is melted and recasted in to 3 spherical balls.Two of the balls have diameter 1.5cm and 2cm respectively

Answer 1

Answer:

Step-by-step explanation:

Volume of original spherical ball = 4/3πr3 = 4/3πx(3/2)^3

Total volume of all balls will be equal. So equation will be

Volume of original = vol of 3 balls

4/3π(3/2)^3 = 4/3π(3/4)^3+4/3π(1)^3+4/3πr^3

We need to find dia of 3rd ball

From above equation we get radius =5/4 cm

So dia of 3rd ball will be 2.5 cm