A Spherical Ball Of Mass 20Kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground and then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height 20 m above the ground. The velocity attained by the ball is:
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Answer:
For the potential energy, only the difference between the initial and final points count.
So this difference is 100−20=80 m
Conservation of energy
2
1
mv
2
=mgh
0.5v
2
=10×80
⇒v=40 m/s
Option A.
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