Question

A spherical ball of mass 20kg is stationary at the top of a hill of height 100m . it rolls down a smooth surface to the ground , then climbs up another hill of height 30m and finally tools down to a horizontal base at a height of 20m above the ground . The velocity attained by the ball is ? [AIEEE 2005]​

Answer 1

Answer:

40 m/sec

Explanation:

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Answer 2

Given:

• Mass of Ball (m) = 20kg
• Height (h) = 100m
• Other Hill's Height (h) = 30m
• Horizontal height = 20m

To Find:

• The velocity attained by the ball is ?

Solution:

For the Potential energy, we have to count the Initial and final velocity;

we get;

Difference is: 100m - 20m = 80m

Conservation of Energy,

${\sf\purple{ \dfrac{1}{2} mv^2 = mgh}} \\ \\ \hookrightarrow{\sf{ 0.5v^2 = 10 \times 80 }} \\ \\ \hookrightarrow{\sf\blue{ v = 40 \: m \ s}}$

Hence,

The Velocity of the spherical ball is 40 m/s.