Question

A spherical ball of radius 10 cm rolls on the

ground through an angle of 30°. The linear

distance covered by the ball is approximately equal

to​

Answer 1

Given:

A spherical ball of radius 10 cm rolls on the ground through an angle of 30°.

To find:

The linear distance covered by the ball.

Calculation:

We will consider that the ball rotates along one of the axis passing through the diametric ends .

For 360° full rotation , the ball would have covered the whole circumference (considering a circular part of the sphere)

Therefore , for 30° rotation , it will cover a linear distance equal to :

$\rm{ \therefore \: d = \dfrac{2\pi r}{360 \degree} \times 30 \degree}$

$\rm{ = > \: d = \dfrac{2\pi r}{12 } }$

$\rm{ = > \: d = \dfrac{\pi r}{6 } }$

Putting available values :

$\rm{ = > \: d = \dfrac{\pi \times 10}{6 } }$

$\rm{ = > \: d = \dfrac{5\pi }{3 } \: cm}$

So final answer is :

The sphere will cover a linear distance of 5π/3 cm.

Answer 2

Answer:

hope it will help you

Step-by-step explanation:

ans is 5×pii/3 cm