A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of the balls are 1.5 cm and 2 cm. Find the diameter of the third ball.
Answers
Answer:
The diameter of the third ball is 5 cm.
Step-by-step explanation:
Given :
Let the Radius of the third ball be r3
Radius of the spherical ball , R = 3 cm
Radius of the first ball, r1 = 1.5 cm
Radius of the second ball, r2 = 2 cm
Volume of the spherical ball, V = 4/3πR³
Volume of the spherical ball is equal to the volume of the 3 small spherical balls.
Volume of the spherical ball, V = Volume (V1) of first ball + Volume (V2) of second ball + Volume of third ball (V3)
4/3πR³ = 4/3πr1³ + 4/3πr2³ + 4/3πr3³
4/3πR³ = 4/3π (r1³ + r2³ + r3³)
R³ = (r1³ + r2³ + r3³)
3³ = (1.5³ + 2³ + r3³)
27 = 3.375 + 8 + r3³
27 = 11.375 + r3³
r3³ = 27 - 11.375
r3³ = 15.625
r3 = ³√15.625
r3 = ³√ 2.5 × 2.5 × 2.5
r3 = 2.5 cm
Radius of the third ball = 2.5 cm
Diameter of the third ball = 2 × r3 = 2 × 2.5 = 5 cm
Diameter of the third ball = 5 cm
Hence, the diameter of the third ball is 5 cm.
HOPE THIS ANSWER WILL HELP YOU...
volume of spherical ball of radius 1.5cm=4/3π×3.375...eq2
volume of spherical ball of radius 2 cm=4/3π×8.......eq3
volume of spherical ball of radius x=4/3πx^3.....eq4
According to the question
eq1=eq2+eq3 +eq4
4/3π27=4/3π(3.375+8+x^3)
27=11.375+x^3
x^3=15.625cm^3
x=2.5cm
Radius of third spherical ball=2.5cm
Diameter=5cm
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