A spherical balloon of radius r subtends an angle theta at the eye of an observer. If the angle of elevation of
its centre is alpha, find the height of the centre of the balloon.
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Let O be the center of the balloon of radius r and P be the eye of an observer
Let PA and PB be the tangents from P to the balloon.
Then, ∠APX=α
∠APO=∠BPO=
2
α
Let OL be the tar drawn from center O on PX
∠OPL=β
In △OAP
sin
2
α
=
OP
OA
=
OP
r
OP=rcsc
2
α
In △OPL,sinβ=
OP
OL
OL=OPsinβ=rcsc
2
α
.sinβ
h=rcsc
2
α
sinβ
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