Physics, asked by akshatgambhir1737, 1 year ago

A spherical bob of diameter 3 cm having mass 100g is attached at the end of a string of length of 48.5cm find angular velocity and tension in the string

Answers

Answered by abhi178
2

angular velocity = 62.8 rad/s and force = 197.192 N

The Bob is constantly rotated , N = 600 rpm.

diameter of Bob, d = 3cm

so, radius of Bob, r = 1.5 cm

then, length of rod from centre of mass of Bob, l = 48.5 cm + 1.5cm = 50cm

now, angular velocity ,ω = 2πN/60 rad/s

= 2π × 600/60 = 20π = 62.8 rad/s

now, force , F = mrω²

= 100g × 50cm × (62.8 rad/s)²

= 0.1kg × 0.5 m × 3943.84 rad/s²

= 197.192 N

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Answered by Anonymous
0

\huge\bold\purple{Answer:-}

The Bob is constantly rotated , N = 600 rpm.

diameter of Bob, d = 3cm

so, radius of Bob, r = 1.5 cm

then, length of rod from centre of mass of Bob, l = 48.5 cm + 1.5cm = 50cm

now, angular velocity ,ω = 2πN/60 rad/s

= 2π × 600/60 = 20π = 62.8 rad/s

now, force , F = mrω²

= 100g × 50cm × (62.8 rad/s)²

= 0.1kg × 0.5 m × 3943.84 rad/s²

= 197.192 N

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