Question

A spherical canon ball 28 cm diameter is melted and cast into a right circular conical mould the base of which is 35 cm in diameter . Find the height of the cone ,correct to one place of decimal.

Answer 1

Volume of spherical canon ball = 784π/3 cubic cm.
Let height of cone = h cm.
volume of cone = (1225πh/12)cubic cm.
Acc. to question ,
784π/3=1225πh/12
therefore ,
h = (784/36.2)cm.

Answer 2

AnswEr:

Let h cm be the height of the cone.

We have,

• Diameter of spherical canon ball = 28 cm

• Radius of base of spherical cannon ball = 14 cm

• Diameter of base of the cone = 35 cm

• Radius of base of the cone equal $\sf\dfrac{35}{2}cm$

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Now, Volume of the cone = Volume of spherical canon ball

$= \sf \frac{1}{3} \times \pi \times ( \frac{35}{2} ) {}^{2} \times h = \frac{4}{3} \times \pi \times {(14)}^{3} \\ \\ = \sf ( \frac{35}{2} ) {}^{2} h = 4 \times (14) {}^{3} \\ \\ \implies \sf h = ( 4 \times 14 \times 14 \times 14 \times \frac{2}{35} \times \frac{2}{35} ) cm \\ \\ \implies \sf \: h = (4 \times 2 \times 2 \times 14 \times \frac{2}{5} \times \frac{2}{5} )cm \\ \\ = \sf \: \frac{896}{25}cm = 35.84cm$

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