A spherical drop of mercury of radius R has a Capacitance given by C = 4πϵ0 R. If two such drops combine to form a single larger drop, what is its capacitance?A spherical drop of mercury of radius R has a Capacitance given by C = 4πϵ0 R. If two such drops combine to form a single larger drop, what is its capacitance?
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The capacitance will be
1.26 C
Explanation:
- As the capacitance of a conducting sphere of radius R is C = 4πϵ0 R;
- It is proportional to the radius of the circle
- When two droplets are combined, the volume of the new droplet is twice
- As the volume is proportional to the radius cubed, so the radius of the combined droplet is (2)1/3 = 1.26
- 1.26 times of the smaller droplets and capacitance increases the same way
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