Question

A spherical drop of mercury of radius R has a Capacitance given by C = 4πϵ0 R. If two such drops combine to form a single larger drop, what is its capacitance?

Answer 1

Answer:

if 2 drop form large drop then its volume equal n×(4/3)πr^3=(4/3)πR^3 where n is no of molecule of small drop and ,r is radius of small drop R is radius of big drop then after solve n^1/3 r =R And capicitance is directly promotional to radius n^1/3 c= C