A spherical drop of mercury of radius r has capacitance given by= 4πɛ0r. if 2 such drops combine to form a big drop, what is its capacitance?
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Let potential f 1 drop = Kq/r =V
Volume of n drops = volume of bigger drop
n 4/3 pi (r)^3 = 4/3 pi (R)^3
Therefore , R = ( (n)^1/3) r
also charge remains conserved
charge on 1 drop = q
charge on big drop containing n drops = (nq)
Therefore potential on big drop = K (nq)/ ((n)^1/3)r
=(( n)^2/3) Kq/r
= (( n)^2/3) V
Volume of n drops = volume of bigger drop
n 4/3 pi (r)^3 = 4/3 pi (R)^3
Therefore , R = ( (n)^1/3) r
also charge remains conserved
charge on 1 drop = q
charge on big drop containing n drops = (nq)
Therefore potential on big drop = K (nq)/ ((n)^1/3)r
=(( n)^2/3) Kq/r
= (( n)^2/3) V
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