Question

A spherical iron ball is dropped into a
cylindrical vessel of diameter 14 cm,
containing water. If the water level is
increased by 9 cm, then the radius of the
ball is​

Answer 1

Answer:

volume of ball = volume of water rised

4/3×22/7×r^3 = 22/7×r^2×h

4/3×r^3=7^2×9 since diameter of vessel is 14cm

r^3=(49×9×3)/4

r^3=(49×27)/4

r=cube root (49×27)/4

r=3cube root49/4 cm

Answer 2

Step-by-step explanation:

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