Question

A spherical iron ball of radius 10 cm is coated with a layer of ice of uniform thickness that melts at a rate of 50 cm³/min. When the thickness of the ice is 5 cm, then the rate at which the thickness (in cm/min) of ice decreases is
(A) 1/36π
(B) 5/6π
(C) 1/9π
(D) 1/18π

Answer 1

Answer:

A spherical iron ball of radius 10 cm is coated with a layer of ice of uniform thickness that melts at a rate of 50 cm³/min. When the thickness of the ice is 5 cm, then the rate at which the thickness (in cm/min) of ice decreases is

(A) 1/36π

(B) 5/6π

(C) 1/9π

(D) 1/18πq✓✓

Answer 2

Answer:1/33π

Step-by-step explanation:

Volume of iron ball=4/3 πr³

=4/3 π1000

=4000π/3

Volume of ball including ice =4/3 πr³

=4/3 π3375

=13500π/3

Volume of ice=Total volume(including the ice ones)-Volume of iron ball

=13500π/3-4000π/3

=9500π/3

Decrease in thickness at cm/sec.=50*3/9500π

=3/190π

=1/33π

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