A spherical iron Ball of radius 9cm is melted and recast into three spherical balls.If radius of two balls be 1cm and 8cm, find the radius of the third ball.
With method if possible..
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volume of 9cm ball=4/3*pie*9^3=sum of volume of the small balls=4/3*pie(1^3+8^3+r^3)
so 1+512+r^3=729
so r^3=729-512-1=216
so r=(216)^1/3=6(ans)
so 1+512+r^3=729
so r^3=729-512-1=216
so r=(216)^1/3=6(ans)
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