Question

A SPHERICAL LIQUID DROP IS DIVIDED INTO 27 DROPLETS OF EQUAL SIZE. IF RADIUS OF DROP IS 'R' AND SURFACE TENSION 'T' , THE WORK DONE IN PROCESS IS ?
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Answer 1

I hope it'll help you :) have a nice day

Answer 2

Let us say r is the radius of each eight of the bubble. Since volume of water remains the same, we have

4/3πR³

=8×4/3πr³

⇒r= R/2

So the work done in this process will be = change in the surface energy i.e.

(8×4πr²×T)−(4πR²×T)

=(8×4π (R/2)²×T)−(4πR²×T)

∵r= R/2

=8πR²T−4πR²T

=4πR²T