Question

A spherical marble, of refractive index
1.5 and curvature 1.5 cm, contains a tiny
air bubble at its centre. Where will it
appear when seen from outside?
(A) I cm inside
(B) at the centre
(C) 5/3 cm inside
(D) 2 cm inside​

Answer 1

Answer:5/3 cm inside.

Explanation:

Since, the bubble is inside the spherical marble which is having a refractive index of 1.5. The observer will see the image formed due to the reflection in the all those spherical surfaces. So, on suing the lens maker formulae we will get where will the image form.

So, μ1/v - μ2/u = (μ2 - μ1)/R where μ1 and μ2 are the refractive index of air and glass respectively and R is the radius of curvature 1.5. So, on substituting the values we will get v. So, 1/v - 1.5/0.75 = 1-1.5/1.5 which on solving we will get that 1/v - 2 = 1/3 or v = 5/3 cm inside the marble.

Answer 2

Answer:

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