A spherical planet far out in space has a mass M and diameter D. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to..?
Answers
Answered by
106
as we know g = GM/R²
R= D/2
so,
g = GM/ (D/2)²
= 4GM/ D²
so as the mass of the planet = M
diameter = D
than g = 4GM/ D²
R= D/2
so,
g = GM/ (D/2)²
= 4GM/ D²
so as the mass of the planet = M
diameter = D
than g = 4GM/ D²
Answered by
34
As the mass of planet= M
Diameter =D
So we have,g= GM/R^2
And radius is the half of diameter,
R= D/2
g= GM/(D/2)^2
=4GM/D^2
Similar questions