Question

A spherical planet has a mass 'Mo' and diameter 'Do'. An object of mass 'm' on the surface of this planet will experience a gravitational pull which is
equal to
GM m
D
4 GM m
D
2 GM m
D
GM
D​

Answer 1

Explanation:

HEY MATE ........

$mass \: of \: planet \: is \: m \: 0 \\ \\ diameter \: is \: d \: 0 \\ \\ radius = \frac{d \: 0}{2} \\ \\ g = \frac{gm0}{ {r}^{2} } \\ \\ g = \frac{gm0}{ { \frac{d0}{2} }^{2} } \\ \\ g = \frac{4gm0}{( {d0)}^{2} }$

HOPE IT HELPS YOU

Answer 2

Explanation:

A spherical planet far out in space has a mass M0 and diameter D0. A particle of mass m falling freely near the surface of this planet will experience an accelertion due to gravity which is equal to. =D0. Then g=4GM0D20.