A spherical shell of iron of inner radius 7 cm and thickness 3.5 cm is melted and converted into solid spherical balls of radius 3.5 cm. How many balls can be made?
Ans.=19
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Answered by
8
see the pic
Remember that in this at a place I have used
a minus b whole cube formula.
HOPE IT HELPED.
PLEASE MARK IT AS THE BRAINLIEST ANSWER
Remember that in this at a place I have used
a minus b whole cube formula.
HOPE IT HELPED.
PLEASE MARK IT AS THE BRAINLIEST ANSWER
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ameyashrivastav:
This isnt the whole ans.
It is cutted
No i did it as short as i cud
we can do this without any calculator ... see my solution.
Answered by
12
Spherical shell: R1 = 7 cm. R2 = R1 + 3.5 = 10.5 cm
V1 = Volume of iron used in the shell
= volume of outer sphere - volume of empty space inside
= 4π/3 * [ R2³ - R1³] = 4π/3 * [10.5³ - 7³ ] cm³
Volume of the small solid spherical ball = V2 = 4π/3 R³
V2 = 4π/3 * 3.5³ cm³
Number of balls = V1 / V2
= [10.5³ - 7³ ] /3.5³
= [ (3 × 3.5)³ - (2 × 3.5)³ ] / 3.5³
= 3³ - 2³
= 27 - 8 = 19
V1 = Volume of iron used in the shell
= volume of outer sphere - volume of empty space inside
= 4π/3 * [ R2³ - R1³] = 4π/3 * [10.5³ - 7³ ] cm³
Volume of the small solid spherical ball = V2 = 4π/3 R³
V2 = 4π/3 * 3.5³ cm³
Number of balls = V1 / V2
= [10.5³ - 7³ ] /3.5³
= [ (3 × 3.5)³ - (2 × 3.5)³ ] / 3.5³
= 3³ - 2³
= 27 - 8 = 19
:-)
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