Question

.
A spherical shell of metal has a radius of 0.25 m and
carries a charge of 0.2 uC. Calculate the electric field
intensity at a point (i) inside the shell, (ii) just
outside the shell and (iii) 3.0 m from the centre of
the shell
Ans question1(0)
2(2.88*10^4)
3(200)​

Answer 1

Thus the intensity outside the shell will be E = 2.88 x 10^4 N/C

Explanation:

We are given that:

• Radius of shell = 0.25 m
• Charge of sphere = 0.2 uC

Solution:

E = kq / r^2

E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2

E = 9 x 16 x 0.2 x 10^3

E = 28.8 x 10^3 N/C

E = 2.88 x 10^4 N/C

Thus the intensity outside the shell will be E = 2.88 x 10^4 N/C