Question

.A spherical shell of metal has a radius of 0.25 m andcarries a charge of 0.2 uC. Calculate the electric fieldintensity at a point (i) inside the shell, (ii) justoutside the shell and (iii) 3.0 m from the centre ofthe shellAns question1(0)2(2.88*10^4)3(200)​

Answer 1

Explanation:

E = kq / r^2

E = kq / r^2E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2

E = kq / r^2E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2E = 9 x 16 x 0.2 x 10^3

E = kq / r^2E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2E = 9 x 16 x 0.2 x 10^3E = 28.8 x 10^3 N/C

E = kq / r^2E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2E = 9 x 16 x 0.2 x 10^3E = 28.8 x 10^3 N/CE = 2.88 x 10^4 N/C

E = kq / r^2E = 9 x 10^9 x 0.2 x 10^-6 / ( 1/4)^2E = 9 x 16 x 0.2 x 10^3E = 28.8 x 10^3 N/CE = 2.88 x 10^4 N/CThus the intensity outside the shell will be E = 2.88 x 10^4 N/C