Question

A spherical surface is fixed on ground. Its radius is 5 m. A block is placed some height below the
top most point. If coefficient of friction between block and sphere is 0.75. Find the minimum height
(in metre) of block above ground so that it does not slip

Answer 1

Answer:

mg cosθ=

R

mv

2

......(i)

Mechanical energy conservation :

2

1

mv

2

=mgR(1−cosθ) ......(ii)

From (i) and (ii) ⇒cosθ=

3

2

Now, ⇒v=

Rgcosθ

=

0.6×10×

3

2

=2m/s