Question

A spherr of 20kg is attracted by a second sphere of mass 50kg with a force equal to 0.01gf G=6.67×10^-11Nm^2kg^-2, calculate the distance between them

Answer 1

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Answer 2

Solution:

let, m1 be the mass of first sphere.

m2 be the mass of second sphere.

r be the distance between the spheres.

F12 be the force on first sphere due to second sphere.

F21 be the force on second sphere due to first sphere.

G be the universal gravitational constant.

here, given in the question that

m1 = 20kg

m2 = 50kg

F12 = 0.01gf = 9.8*10^-5 N

G = 6.67*10^-11 Nm^2kg^-2

now, from universal low of gravitation

F12 = F21

F21 = 9.8*10^-5

Gm1m2/r^2 = 9.8*10^-5

r^2 = Gm1m2/9.8*10^-5

r^2 = 6.67*10^-11*20*50/9.8*10^-5

r^2 = 680.61*10^-6

r^2 = 6.8061*10^-4

r = 2.609*10^-2 m

therefore, the distance between m1 and m2 is 2.609*10^-2 m.