Question

a sphre rotating about its diameter has a rotational K.E of 360 j. if its angular speed is 30rad / s its moment of inertia is​

Answer 1

Answer:

➡️➡️Since it is rotating then only take rotational kinetic energy.

Rotational K.E.

\begin{gathered}kinetic \: energy = \frac{1}{2} i \: {w}^{2} \\ \\ 360 = \frac{1}{2} i {(30)}^{2} \\ i = \frac{720}{900}\end{gathered}kineticenergy=21iw2360=21i(30)2i=900720 

Hope it will help you‼️

Answer 2

Explanation:

KE = 1/2 I w^2 = 360 J

I = 2x 360 / 900 = 0.8 Kg M^2