A spider tries to climb a wall 10 block high it started climbing at 6 o'clock in the morning the spider climbs 2 blocks in 1 hour and take rest for 1 hour while resting it fall back by the force of gravity down by one block at what time will it reach the top
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Answer:
Spider will reach at top by 11 :00 PM
Step-by-step explanation:
A spider tries to climb a wall 10 block high it started climbing at 6 o'clock in the morning the spider climbs 2 blocks in 1 hour and take rest for 1 hour while resting it fall back by the force of gravity down by one block at what time will it reach the top
Spider climb 2 block in 1 hr
& then slip 1 block in 1 hr while taking rest
so with in 2 hr it climbs one block
So Spider climbs 8 block in 8*2 = 16 hrs
Now in next 1 hr spider will climb 2 blocks
so Spider will reach at Top in 16 + 1 = 17 Hr
6:00 AM + 17 hrs = 23 o'clock = 11 :00 PM
Spider will reach at top by 11 :00 PM
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