Math, asked by guri576437, 1 year ago

A spider tries to climb a wall 10 block high it started climbing at 6 o'clock in the morning the spider climbs 2 blocks in 1 hour and take rest for 1 hour while resting it fall back by the force of gravity down by one block at what time will it reach the top​

Answers

Answered by amitnrw
17

Answer:

Spider will reach at top by 11 :00 PM

Step-by-step explanation:

A spider tries to climb a wall 10 block high it started climbing at 6 o'clock in the morning the spider climbs 2 blocks in 1 hour and take rest for 1 hour while resting it fall back by the force of gravity down by one block at what time will it reach the top​

Spider climb 2 block in 1 hr

& then slip 1 block in 1 hr while taking rest

so with in 2 hr  it climbs one block

So Spider climbs 8 block in 8*2 = 16 hrs

Now in next 1 hr spider will climb 2 blocks

so Spider will reach at Top in  16 + 1 = 17 Hr

6:00 AM + 17 hrs = 23 o'clock  = 11 :00 PM

Spider will reach at top by 11 :00 PM

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