Question

A spinner is divided into 3 equal sections, with sections labeled 1, 2, and 3. What is the probability of spinning a 3 on the spinner if you know the arrow landed on an odd number

Answer 1

Answer:

The probability of the arrow landing on the $3^{rd}$ section is $\frac{1}{2}$

Explanation:

The probability of an event is $P(A)=\frac{n(A)}{n(S)}$

where n(A) is the number of favorable events and n(S) is the total number of events.

Step-by-step explanation:

Step-1:

The board is divided into three equal sections.

Now it is given that it is landing on an odd number.

So the only two events that are possible are $1, 3$.

Total number of events are $2$.

Step-2:

We want to know the probability of the arrow landing on $3$.

So the number of favorable events is $1$.

Step-3:

The probability of the given event is $P(3)=\frac{1}{2}$

Hence, the probability of the arrow landing on $3$ known that it lands on an odd number is $\frac{1}{2}$.

What is the probability:

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How to find the probability of an event:

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